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The negatively charged state calculations have been done to show how many holes can stabilized the dopants interactions. In (N, N) co-doped case, two holes are necessary to stabilize the chemical bond between two dopants. However, for (N, P) or (C, S) co-doped cases, only one hole (negatively charged case by adding one electron in the calculation) is enough to stabilize the chemical bonds between N and P, or C and S
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The negatively charged state calculations have been done to show how many holes can stabilized the dopants interactions. In (N, N) co-doped case, two holes are necessary to stabilize the chemical bond between two dopants. However, for (N, P) or (C, S) co-doped cases, only one hole (negatively charged case by adding one electron in the calculation) is enough to stabilize the chemical bonds between N and P, or C and S.
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