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J. Jiang, R. Saito, A. Grüneis, G. Dresselhaus, and M. S. Dresselhaus, Carbon 42, 3169 (2004). 10.1016/j.carbon.2004.07.028
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Jiang, J.1
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A. Zarifi and T. G. Pedersen, Phys. Rev. B 80, 195422 (2009). 10.1103/PhysRevB.80.195422
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Zarifi, A.1
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Goupalov, S.V.1
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5
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77955382101
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In particular, it fails to predict the order of the energy bands.
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In particular, it fails to predict the order of the energy bands.
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6
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0013148135
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10.1103/PhysRevB.66.155404
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E. L. Ivchenko and B. Z. Spivak, Phys. Rev. B 66, 155404 (2002). 10.1103/PhysRevB.66.155404
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Ivchenko, E.L.1
Spivak, B.Z.2
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7
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77955362793
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As a consequence of the overlap integral of the tight-binding method being neglected. See Ref..
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As a consequence of the overlap integral of the tight-binding method being neglected. See Ref..
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8
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77955406487
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The state with μ=N/2, K2 =0 corresponds to the M point in the reciprocal space of graphene. If the origin in the reciprocal space were moved to this point then the time-reversal operation would relate the electronic states of a carbon nanotube characterized by the opposite two-dimensional k vectors (the electron spin is neglected). For the (4,2) nanotube N=28.
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The state with μ = N / 2, K 2 = 0 corresponds to the M point in the reciprocal space of graphene. If the origin in the reciprocal space were moved to this point then the time-reversal operation would relate the electronic states of a carbon nanotube characterized by the opposite two-dimensional k vectors (the electron spin is neglected). For the (4,2) nanotube N = 28.
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9
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77955372985
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As was pointed out in Ref., this is not the case of Fig. 6 in Ref. describing optical transitions in a (10, 10) armchair nanotube.
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As was pointed out in Ref., this is not the case of Fig. 6 in Ref. describing optical transitions in a (10, 10) armchair nanotube.
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10
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77955381358
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For μ=11, K2 =π/T one has K1 =11 (5 b1 +4 b2 ) /28, K2 =1/2 (2 b1 -4 b2 ) /28, where b1 and b2 are the reciprocal-lattice vectors of graphene (Ref.). Thus, one has K1 + K2 =2 b1 +3/2 b2, which corresponds to the M point in the reciprocal space of graphene.
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For μ = 11, K 2 = π / T one has K 1 = 11 (5 b 1 + 4 b 2) / 28, K 2 = 1 / 2 (2 b 1 - 4 b 2) / 28, where b 1 and b 2 are the reciprocal-lattice vectors of graphene (Ref.). Thus, one has K 1 + K 2 = 2 b 1 + 3 / 2 b 2, which corresponds to the M point in the reciprocal space of graphene.
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