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For the sake of simplicity, we consider the spinless case only. Spin-degenerate channels can be introduced without any significant consequence on orbital entanglement due to separability of spin and orbital degrees of freedom.
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We identify the two levels of each qubit with the pair of outgoing channels at each side of the interferometer (along which only one particle electron or hole propagates). Defining the upper state of each qubit as the electron excitation, |1« = C (L,R ) 1 † | 0̄ », and the lower state as the hole one, |0« = C (L,R ) 2 | 0̄ », the first two terms in Eq. read as t1 t2*- | 10 « - r1 r2*| 01 ».
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