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69949181799
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Note that if one would replace n by its adiabatic approximation not only in Eq. 18 but also in Eq. 17, one would obtain Ic =â1/2 I2 and p2+ =0 for 0â‰Iâ‰1. Similarly, for 1â‰Iâ ‰2, one would obtain Ic =â1/2 (2âI) 2 and p0+ =0.
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Note that if one would replace n by its adiabatic approximation not only in Eq. 18 but also in Eq. 17, one would obtain Ic =â1/2 I2 and p2+ =0 for 0â‰Iâ‰1. Similarly, for 1â‰Iâ ‰2, one would obtain Ic =â1/2 (2âI) 2 and p0+ =0.
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24
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69949184645
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We did not use the full time-dependent density in Eq. 25 because of the technical problems mentioned above. However, we also mimicked this dynamical effect by weighing the integral with the time-dependent ionization I and obtained practically the same results.
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We did not use the full time-dependent density in Eq. 25 because of the technical problems mentioned above. However, we also mimicked this dynamical effect by weighing the integral with the time-dependent ionization I and obtained practically the same results.
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