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13
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-
85036251129
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Sov. Phys. JETPS. A. Brazovskii42, 497 (1976);
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(1976)
, vol.42
, pp. 497
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-
Brazovskii, S.A.1
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20
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-
85036177043
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-
The second term in brackets corresponds to (Formula presented) where (Formula presented) (Formula presented) are the unit vectors along x and y. (Formula presented) is the rotation matrix (Formula presented) and (Formula presented) are the directions in the molecular vector space along the molecular polarization, and in the perpendicular plane, respectively. (Formula presented) is taken normal to the molecular mirror plane. Note that a (Formula presented) term, where (Formula presented) is a third vector order parameter, is forbidden by the (Formula presented) molecular symmetry
-
The second term in brackets corresponds to (Formula presented) where (Formula presented) (Formula presented) are the unit vectors along x and y. (Formula presented) is the rotation matrix (Formula presented) and (Formula presented) are the directions in the molecular vector space along the molecular polarization, and in the perpendicular plane, respectively. (Formula presented) is taken normal to the molecular mirror plane. Note that a (Formula presented) term, where (Formula presented) is a third vector order parameter, is forbidden by the (Formula presented) molecular symmetry.
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-
-
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21
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-
85036275694
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-
Equation (2) neglects the secondary order parameters transforming as higher-rank tensors and corresponding to terms proportional to (Formula presented)
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Equation (2) neglects the secondary order parameters transforming as higher-rank tensors and corresponding to terms proportional to (Formula presented)
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-
-
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22
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-
85036274389
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-
The effective molecular symmetry depends on the macroscopic symmetry, but these two symmetries do not influence one another in a simple way. For example, in the conventional centrosymmetric uniaxial nematic phase with macroscopic (Formula presented) symmetry the molecules having the symmetry (Formula presented) reach an effective symmetry (Formula presented) The continuous effective symmetry in the polar uniaxial nematic phase results from the absence of the Euler angle α in the corresponding distribution function, as defined by Eq. (2)
-
The effective molecular symmetry depends on the macroscopic symmetry, but these two symmetries do not influence one another in a simple way. For example, in the conventional centrosymmetric uniaxial nematic phase with macroscopic (Formula presented) symmetry the molecules having the symmetry (Formula presented) reach an effective symmetry (Formula presented) The continuous effective symmetry in the polar uniaxial nematic phase results from the absence of the Euler angle α in the corresponding distribution function, as defined by Eq. (2).
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-
-
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25
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0000488896
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A second-order isotropic-uniaxial polar nematic (Formula presented) transition has been predicted, using a different continuum approach by V. L. Indenbom, Sov. Phys. Crystallogr. 21, 632 (1976), and A. G. Khachaturyan (Ref. 11).
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(1976)
Sov. Phys. Crystallogr.
, vol.21
, pp. 632
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-
Indenbom, V.L.1
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27
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0012015742
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P. I. C. Texeira, Liq. Cryst. 25, 721 (1998), and references therein.
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(1998)
Liq. Cryst.
, vol.25
, pp. 721
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Texeira, P.I.C.1
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