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The equation resulting from the tendency line is y = 22.602 Ln(x) + 1.8858. This explains a variance equivalent R2 = 0.9863. Its derivative is defined by y' = 22.602/x. The equation of the straight line is y = 1.087x, R2 = 1, with derivative y' = 1.087. In order to find the tangent point, the equation 22.602/x = 1.087 was solved, resulting in the value x = 20.79
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The equation resulting from the tendency line is y = 22.602 Ln(x) + 1.8858. This explains a variance equivalent R2 = 0.9863. Its derivative is defined by y' = 22.602/x. The equation of the straight line is y = 1.087x, R2 = 1, with derivative y' = 1.087. In order to find the tangent point, the equation 22.602/x = 1.087 was solved, resulting in the value x = 20.79.
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